3.202 \(\int \frac{x^2}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx\)

Optimal. Leaf size=107 \[ -\frac{a^2}{4 b^3 (a+b x)^3 \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{2 a}{3 b^3 (a+b x)^2 \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{1}{2 b^3 (a+b x) \sqrt{a^2+2 a b x+b^2 x^2}} \]

[Out]

-a^2/(4*b^3*(a + b*x)^3*Sqrt[a^2 + 2*a*b*x + b^2*x^2]) + (2*a)/(3*b^3*(a + b*x)^
2*Sqrt[a^2 + 2*a*b*x + b^2*x^2]) - 1/(2*b^3*(a + b*x)*Sqrt[a^2 + 2*a*b*x + b^2*x
^2])

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Rubi [A]  time = 0.132656, antiderivative size = 107, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.083 \[ -\frac{a^2}{4 b^3 (a+b x)^3 \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{2 a}{3 b^3 (a+b x)^2 \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{1}{2 b^3 (a+b x) \sqrt{a^2+2 a b x+b^2 x^2}} \]

Antiderivative was successfully verified.

[In]  Int[x^2/(a^2 + 2*a*b*x + b^2*x^2)^(5/2),x]

[Out]

-a^2/(4*b^3*(a + b*x)^3*Sqrt[a^2 + 2*a*b*x + b^2*x^2]) + (2*a)/(3*b^3*(a + b*x)^
2*Sqrt[a^2 + 2*a*b*x + b^2*x^2]) - 1/(2*b^3*(a + b*x)*Sqrt[a^2 + 2*a*b*x + b^2*x
^2])

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Rubi in Sympy [A]  time = 7.30753, size = 63, normalized size = 0.59 \[ \frac{x^{3} \left (2 a + 2 b x\right )}{8 a \left (a^{2} + 2 a b x + b^{2} x^{2}\right )^{\frac{5}{2}}} + \frac{x^{3}}{12 a^{2} \left (a^{2} + 2 a b x + b^{2} x^{2}\right )^{\frac{3}{2}}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  rubi_integrate(x**2/(b**2*x**2+2*a*b*x+a**2)**(5/2),x)

[Out]

x**3*(2*a + 2*b*x)/(8*a*(a**2 + 2*a*b*x + b**2*x**2)**(5/2)) + x**3/(12*a**2*(a*
*2 + 2*a*b*x + b**2*x**2)**(3/2))

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Mathematica [A]  time = 0.0228407, size = 44, normalized size = 0.41 \[ \frac{-a^2-4 a b x-6 b^2 x^2}{12 b^3 (a+b x)^3 \sqrt{(a+b x)^2}} \]

Antiderivative was successfully verified.

[In]  Integrate[x^2/(a^2 + 2*a*b*x + b^2*x^2)^(5/2),x]

[Out]

(-a^2 - 4*a*b*x - 6*b^2*x^2)/(12*b^3*(a + b*x)^3*Sqrt[(a + b*x)^2])

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Maple [A]  time = 0.007, size = 37, normalized size = 0.4 \[ -{\frac{ \left ( bx+a \right ) \left ( 6\,{b}^{2}{x}^{2}+4\,abx+{a}^{2} \right ) }{12\,{b}^{3}} \left ( \left ( bx+a \right ) ^{2} \right ) ^{-{\frac{5}{2}}}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  int(x^2/(b^2*x^2+2*a*b*x+a^2)^(5/2),x)

[Out]

-1/12*(b*x+a)*(6*b^2*x^2+4*a*b*x+a^2)/b^3/((b*x+a)^2)^(5/2)

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Maxima [A]  time = 0.806513, size = 77, normalized size = 0.72 \[ -\frac{a^{2} b^{2}}{4 \,{\left (b^{2}\right )}^{\frac{9}{2}}{\left (x + \frac{a}{b}\right )}^{4}} + \frac{2 \, a b}{3 \,{\left (b^{2}\right )}^{\frac{7}{2}}{\left (x + \frac{a}{b}\right )}^{3}} - \frac{1}{2 \,{\left (b^{2}\right )}^{\frac{5}{2}}{\left (x + \frac{a}{b}\right )}^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate(x^2/(b^2*x^2 + 2*a*b*x + a^2)^(5/2),x, algorithm="maxima")

[Out]

-1/4*a^2*b^2/((b^2)^(9/2)*(x + a/b)^4) + 2/3*a*b/((b^2)^(7/2)*(x + a/b)^3) - 1/2
/((b^2)^(5/2)*(x + a/b)^2)

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Fricas [A]  time = 0.225739, size = 88, normalized size = 0.82 \[ -\frac{6 \, b^{2} x^{2} + 4 \, a b x + a^{2}}{12 \,{\left (b^{7} x^{4} + 4 \, a b^{6} x^{3} + 6 \, a^{2} b^{5} x^{2} + 4 \, a^{3} b^{4} x + a^{4} b^{3}\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate(x^2/(b^2*x^2 + 2*a*b*x + a^2)^(5/2),x, algorithm="fricas")

[Out]

-1/12*(6*b^2*x^2 + 4*a*b*x + a^2)/(b^7*x^4 + 4*a*b^6*x^3 + 6*a^2*b^5*x^2 + 4*a^3
*b^4*x + a^4*b^3)

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Sympy [F]  time = 0., size = 0, normalized size = 0. \[ \int \frac{x^{2}}{\left (\left (a + b x\right )^{2}\right )^{\frac{5}{2}}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate(x**2/(b**2*x**2+2*a*b*x+a**2)**(5/2),x)

[Out]

Integral(x**2/((a + b*x)**2)**(5/2), x)

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GIAC/XCAS [A]  time = 0.559982, size = 4, normalized size = 0.04 \[ \mathit{sage}_{0} x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate(x^2/(b^2*x^2 + 2*a*b*x + a^2)^(5/2),x, algorithm="giac")

[Out]

sage0*x